Prosze o pomoc z zadaniem 5.52 i 5.53

5.52 a) W(x)=2x^2(x^2-3x-4)=2x^2(x-4)(x+1) c) W(x)=x^4-18x^2+81=(x^2-9)(x^2-9)=(x+3)(x-3)(x+3)(x-3)=(x+3)^2(x-3)^2 e) W(x)=(x^2-3x)^2-9x^2=(x^2-3x)^2-(3x)^2=(x^2-3x+3x)(x^2-3x-3x)=x^2(x^2-6x)=x^3(x-6) g) W(x)=4x^3+4x^2-9x-9=4x^2(x+1)-9(x+1)=(x+1)((2x)^2-3^2)=(x+1)(2x+3)(2x-3) b) W(x)=x^4-81=((x^2)^2-9^2)=(x^2+9)(x^2-9)=(x^2+9)(x+3)(x-3) d) W(x)=(x^2+1)^2-4=(x^2+1)^2-2^2=(x^2+1+2)(x^2+1-2)=(x^2+3)(x^2-1)=(x^2+3)(x+1)(x-1) f) W(x)=5x(3x-2)+9x^2+12x-4=5x(3x-2)+(3x-2)^2=(5x+3x-1)(3x-2)=(8x-1)(3x-2) h) W(x)=3x^3+4x^2-27x-36=x^2(3x+4)-9(3x+4)=(3x+4)(x^2-9)=(3x+4)(x+3)(x-3) 5.53. a) W(x)=15x^3-35x^2+6x-14=5x^2(3x-7)+2(3x-7)=(5x^2+2)(3x-7) c) W(x)=4x^4-4x^2+1=(2x^2-1)^2=4(x+{\sqrt{2}\over2})^2(x-{\sqrt{2}\over2})^2 e) W(x)=3x^3+3x^2-18x=3x(x^2+x-6)=3x(x+3)(x-2) g) W(x)=2x^3+5x^2-3x=2x(x^2+{5\over2}x-{3\over2})=2x(x+3)(x-{1\over2})=x(x+3)(2x-1) b) W(x)=x^4+8x^2+7=x^4+x^2+7x^2+7=x^2(x^2+1)+7(x^2+1)=(x^2+7)(x^2+1) d) W(x)=(9x^2-6x+1)-(4x^2+12x+9)=(3x-1)^2-(2x+3)^2=(3x-1+2x+3)(3x-1-2x-3)=(5x+2)(x-4) f) W(x)=-5x^3-10x^2+15x=-5x(x^2+2x-3)=-5x(x+3)(x-1) h) W(x)=3x^4+13x^3-10x^2=x^2(3x^2+13x-10)=x^2(x+5)(x-{2\over3})